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Polynomial Long Division and Megan Moroney – Mean Green Math
A brief clip from Megan Moroney's video "I'm Not Pretty" correctly uses polynomial long division to establish that $latex 2x+3$ is a factor of $latex 2x^4+5x^3+7x^2+16x+15$. Even more amazingly, the fact that the remainder is $latex 0$ actually fits artistically with the video. https://www.youtube.com/watch?v=SZm8ZxeVlCo And while I have her music on my mind, I can't…
Mathematical Allusions in Shantaram: Index – Mean Green Math
I'm doing something that I should have done a long time ago: collecting a series of posts into one single post. The links below show my series on the mathematical allusions in the novel Shantaram. Part 1: The Mandelbrot set Part 2: Stubbornness Part 3: Understanding a mathematical theorem for the first time Part 4:…
Track Meets and Floating Point Numbers – Mean Green Math
Here is one school's results from a (relatively) recent track and field meet. Never mind the name of the school or the names of the athletes representing the school; this is a math blog and not a sports blog, even though I'm an avid sports fan. Furthermore, I have nothing but respect for young people…
Lagrange Points and Polynomial Equations: Index – Mean Green Math
I'm doing something that I should have done a long time ago: collecting a series of posts into one single post. The links below show my series on Lagrange points. Part 1: Introduction Part 2: Finding $latex L_1$ Part 3: Finding $latex L_2$ Part 4: A more analytical way of finding $latex L_1$ and $latex…
Integration Using Schwinger Parametrization – Mean Green Math
I recently read the terrific article Integration Using Schwinger Parametrization, by David M. Bradley, Albert Natian, and Sean M. Stewart in the American Mathematical Monthly. I won't reproduce the entire article here, but I'll hit a couple of early highlights. The basic premise of the article is that a complicated integral can become tractable by…
Relaxing on the Golf Course with SAT problems – Mean Green Math
I enjoyed this little anecdote about how professional golfer Nick Shipley relaxes when long breaks in a round occur. https://twitter.com/KornFerryTour/status/1877908179821944969 See the long-form video from Bryan Bros Golf for more about this talented young golfer. https://www.youtube.com/watch?v=cGPWOUbHHMQ
A vivid illustration of a discontinuous function – Mean Green Math
The essay Singular Limits in the May 2002 issue of Physics Today has a vivid illustration of a discontinuous function $latex F(x)$ which measures the ickiness one feels after eating an apple but observing that proportion $latex x$ of a maggot is still inside the apple. For this function, $latex \displaystyle \lim_{x \to 0^+} F(x)…
High School Students Finding New Proofs of Old Theorems (Part 2): Pythagorean theorem – Mean Green Math
This is a new favorite story to share with students: two high school students recently figured out multiple new proofs of the Pythagorean theorem. Professional article in the American Mathematical Monthly (requires a subscription): https://maa.tandfonline.com/doi/full/10.1080/00029890.2024.2370240 Video describing one of their five ideas: https://www.youtube.com/watch?v=p6j2nZKwf20 Interview in MAA Focus: http://digitaleditions.walsworthprintgroup.com/publication/?i=836749&p=14&view=issueViewer Interview by 60 Minutes: https://www.youtube.com/watch?v=VHeWndnHuQs Praise from…
High School Students Finding New Proofs of Old Theorems (Part 1): Dividing a line segment with straightedge and compass – Mean Green Math
This is one of my all-time favorite stories to share with students: how a couple of ninth graders in 1995 played with Geometer's Sketchpad and stumbled upon a brand-new way of using only a straightedge and compass to divide a line segment into any number of equal-sized parts. This article was published in 1997 and…
Happy Pythagoras Day! – Mean Green Math
Let me take a one-day break from my current series of posts to wish everyone a Happy Pythagoras Day! Today is 7/24/25 (or 24/7/25 in other parts of the world), and $latex 7^2 = 24^2 + 25^2$. Bonus points if you can figure out (without Googling) when the next Pythagoras Days will be. Hint: It's…
Higher derivatives in ordinary speech – Mean Green Math
Just about every calculus student is taught that the first derivative is useful for finding the slope of a curve and finding velocity from position, and that the second derivative is useful for finding the concavity of a curve and finding acceleration from position. I recently came across a couple of quotes that, taken literally,…
Saturday Night Live: Washington’s Dream – Mean Green Math
Happy Fourth of July. I'm a sucker for G-rated ways of using humor to engage students with concepts in the mathematical curriculum. I never thought that Saturday Night Live would provide a wonderful source of material for this effort. https://www.youtube.com/watch?v=JYqfVE-fykk
Horrible False Analogy – Mean Green Math
I had forgotten the precise assumptions on uniform convergence that guarantees that an infinite series can be differentiated term by term, so that one can safely conclude $latex \displaystyle \frac{d}{dx} \sum_{n=1}^\infty f_n(x) = \sum_{n=1}^\infty f_n'(x)$. This was part of my studies in real analysis as a student, so I remembered there was a theorem but…
Predicate Logic and Popular Culture (Part 277): Kellie Pickler – Mean Green Math
Let $latex T$ be the set of all times, and let $latex G(t)$ measure how good day $latex t$ is. Translate the logical statement $latex \exists t_1 < 0 \exists t_2 < 0 \forall t \in T ( (t \ne t_1 \land t \ne t_2) \Longrightarrow (G(t) < G(t_1) \land G(t) < G(t_2)),$ where time $latex 0$ is today.…
Predicate Logic and Popular Culture (Part 276): Heart – Mean Green Math
Let $latex T$ be the set of all times, and let $latex G(t)$ be the statement “I got by on my own at time $latex t$." Translate the logical statement $latex \forall t \in T ( ((t<0) \longrightarrow G(t) ) \land (t \ge 0) \longrightarrow \sim G(t)),$ where time $latex 0$ is today. This matches the opening line of…
Solving Problems Submitted to MAA Journals (Part 7i) – Mean Green Math
The following problem appeared in Volume 131, Issue 9 (2024) of The American Mathematical Monthly. Let $latex X$ and $latex Y$ be independent normally distributed random variables, each with its own mean and variance. Show that the variance of $latex X$ conditioned on the event $latex X>Y$ is smaller than the variance of $latex X$…
Solving Problems Submitted to MAA Journals (Part 7h) – Mean Green Math
The following problem appeared in Volume 131, Issue 9 (2024) of The American Mathematical Monthly. Let $latex X$ and $latex Y$ be independent normally distributed random variables, each with its own mean and variance. Show that the variance of $latex X$ conditioned on the event $latex X>Y$ is smaller than the variance of $latex X$…
Solving Problems Submitted to MAA Journals (Part 7g) – Mean Green Math
The following problem appeared in Volume 131, Issue 9 (2024) of The American Mathematical Monthly. Let $latex X$ and $latex Y$ be independent normally distributed random variables, each with its own mean and variance. Show that the variance of $latex X$ conditioned on the event $latex X>Y$ is smaller than the variance of $latex X$…
Solving Problems Submitted to MAA Journals (Part 7f) – Mean Green Math
The following problem appeared in Volume 131, Issue 9 (2024) of The American Mathematical Monthly. Let $latex X$ and $latex Y$ be independent normally distributed random variables, each with its own mean and variance. Show that the variance of $latex X$ conditioned on the event $latex X>Y$ is smaller than the variance of $latex X$…
Solving Problems Submitted to MAA Journals (Part 7e) – Mean Green Math
The following problem appeared in Volume 131, Issue 9 (2024) of The American Mathematical Monthly. Let $latex X$ and $latex Y$ be independent normally distributed random variables, each with its own mean and variance. Show that the variance of $latex X$ conditioned on the event $latex X>Y$ is smaller than the variance of $latex X$…
Solving Problems Submitted to MAA Journals (Part 7d) – Mean Green Math
The following problem appeared in Volume 131, Issue 9 (2024) of The American Mathematical Monthly. Let $latex X$ and $latex Y$ be independent normally distributed random variables, each with its own mean and variance. Show that the variance of $latex X$ conditioned on the event $latex X>Y$ is smaller than the variance of $latex X$…
Solving Problems Submitted to MAA Journals (Part 7c) – Mean Green Math
The following problem appeared in Volume 131, Issue 9 (2024) of The American Mathematical Monthly. Let $latex X$ and $latex Y$ be independent normally distributed random variables, each with its own mean and variance. Show that the variance of $latex X$ conditioned on the event $latex X>Y$ is smaller than the variance of $latex X$…
Solving Problems Submitted to MAA Journals (Part 7b) – Mean Green Math
The following problem appeared in Volume 131, Issue 9 (2024) of The American Mathematical Monthly. Let $latex X$ and $latex Y$ be independent normally distributed random variables, each with its own mean and variance. Show that the variance of $latex X$ conditioned on the event $latex X>Y$ is smaller than the variance of $latex X$…
Solving Problems Submitted to MAA Journals (Part 7a) – Mean Green Math
The following problem appeared in Volume 131, Issue 9 (2024) of The American Mathematical Monthly. Let $latex X$ and $latex Y$ be independent normally distributed random variables, each with its own mean and variance. Show that the variance of $latex X$ conditioned on the event $latex X>Y$ is smaller than the variance of $latex X$…
Solving Problems Submitted to MAA Journals (Part 6e) – Mean Green Math
The following problem appeared in Volume 97, Issue 3 (2024) of Mathematics Magazine. Two points $latex P$ and $latex Q$ are chosen at random (uniformly) from the interior of a unit circle. What is the probability that the circle whose diameter is segment $latex overline{PQ}$ lies entirely in the interior of the unit circle? Let…
Solving Problems Submitted to MAA Journals (Part 6d) – Mean Green Math
The following problem appeared in Volume 97, Issue 3 (2024) of Mathematics Magazine. Two points $latex P$ and $latex Q$ are chosen at random (uniformly) from the interior of a unit circle. What is the probability that the circle whose diameter is segment $latex overline{PQ}$ lies entirely in the interior of the unit circle? As…
Solving Problems Submitted to MAA Journals (Part 6c) – Mean Green Math
The following problem appeared in Volume 97, Issue 3 (2024) of Mathematics Magazine. Two points $latex P$ and $latex Q$ are chosen at random (uniformly) from the interior of a unit circle. What is the probability that the circle whose diameter is segment $latex \overline{PQ}$ lies entirely in the interior of the unit circle? As…
Solving Problems Submitted to MAA Journals (Part 6b) – Mean Green Math
The following problem appeared in Volume 97, Issue 3 (2024) of Mathematics Magazine. Two points $latex P$ and $latex Q$ are chosen at random (uniformly) from the interior of a unit circle. What is the probability that the circle whose diameter is segment $latex \overline{PQ}$ lies entirely in the interior of the unit circle? As…
Solving Problems Submitted to MAA Journals (Part 6a) – Mean Green Math
The following problem appeared in Volume 97, Issue 3 (2024) of Mathematics Magazine. Two points $latex P$ and $latex Q$ are chosen at random (uniformly) from the interior of a unit circle. What is the probability that the circle whose diameter is segment $latex \overline{PQ}$ lies entirely in the interior of the unit circle? It…
Solving Problems Submitted to MAA Journals (Part 5e) – Mean Green Math
The following problem appeared in Volume 96, Issue 3 (2023) of Mathematics Magazine. Evaluate the following sums in closed form: $latex f(x) = \displaystyle \sum_{n=0}^\infty \left( \cos x - 1 + \frac{x^2}{2!} - \frac{x^4}{4!} \dots + (-1)^{n-1} \frac{x^{2n}}{(2n)!} \right)$ and $latex g(x) = \displaystyle \sum_{n=0}^\infty \left( \sin x - x + \frac{x^3}{3!} - \frac{x^5}{5!} \dots…
Solving Problems Submitted to MAA Journals (Part 5d) – Mean Green Math
The following problem appeared in Volume 96, Issue 3 (2023) of Mathematics Magazine. Evaluate the following sums in closed form: $latex f(x) = \displaystyle \sum_{n=0}^\infty \left( \cos x - 1 + \frac{x^2}{2!} - \frac{x^4}{4!} \dots + (-1)^{n-1} \frac{x^{2n}}{(2n)!} \right)$ and $latex g(x) = \displaystyle \sum_{n=0}^\infty \left( \sin x - x + \frac{x^3}{3!} - \frac{x^5}{5!} \dots…
Solving Problems Submitted to MAA Journals (Part 5c) – Mean Green Math
The following problem appeared in Volume 96, Issue 3 (2023) of Mathematics Magazine. Evaluate the following sums in closed form: $latex f(x) = \displaystyle \sum_{n=0}^\infty \left( \cos x - 1 + \frac{x^2}{2!} - \frac{x^4}{4!} \dots + (-1)^{n-1} \frac{x^{2n}}{(2n)!} \right)$ and $latex g(x) = \displaystyle \sum_{n=0}^\infty \left( \sin x - x + \frac{x^3}{3!} - \frac{x^5}{5!} \dots…
Solving Problems Submitted to MAA Journals (Part 5b) – Mean Green Math
The following problem appeared in Volume 96, Issue 3 (2023) of Mathematics Magazine. Evaluate the following sums in closed form: $latex f(x) = \displaystyle \sum_{n=0}^\infty \left( \cos x - 1 + \frac{x^2}{2!} - \frac{x^4}{4!} \dots + (-1)^{n-1} \frac{x^{2n}}{(2n)!} \right)$ and $latex g(x) = \displaystyle \sum_{n=0}^\infty \left( \sin x - x + \frac{x^3}{3!} - \frac{x^5}{5!} \dots…
Solving Problems Submitted to MAA Journals (Part 5a) – Mean Green Math
The following problem appeared in Volume 96, Issue 3 (2023) of Mathematics Magazine. Evaluate the following sums in closed form: $latex \displaystyle \sum_{n=0}^\infty \left( \cos x - 1 + \frac{x^2}{2!} - \frac{x^4}{4!} \dots + (-1)^{n-1} \frac{x^{2n}}{(2n)!} \right)$ and $latex \displaystyle \sum_{n=0}^\infty \left( \sin x - x + \frac{x^3}{3!} - \frac{x^5}{5!} \dots + (-1)^{n-1} \frac{x^{2n+1}}{(2n+1)!} \right)$.…